Q219 · Practice questionTechnology-freeComplex unfamiliar6 marks
QUESTION 219 (6 marks)
A population satisfies with k>0, N(0)=30 and N(4)=60. Time is in days.
a)[4 marks]
Solve the equation to determine k exactly.
b)[2 marks]
Determine when N first reaches 90.
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) . (b) days.
Worked solution
(a) Separation and partial fractions give . The initial ratio is 1/3, hence C=-ln3. At t=4 the ratio is 1, giving , so k=ln3/480.
(b) At N=90 the ratio is 3. Thus , so and t=8. Growth is positive from 30 to 90, making this the first attainment.
Equivalent mathematically justified methods accepted.
Exact answers unless a decimal accuracy is specified.
Part a: Separate variables.
Part a: Integrate the partial fractions.
Part a: Apply the initial population.
Part a: Use the four-day observation to determine k.
Part b: Use the target logarithmic ratio.
Part b: Obtain 8 days and justify first attainment.
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