Q221 · Practice questionTechnology-freeComplex unfamiliar6 marks
QUESTION 221 (6 marks)
Consider , y nonnegative, with y(0)=0.
a)[2 marks]
Verify that both and for satisfy the initial-value problem.
b)[3 marks]
For , verify the delayed solution: on and for t>c.
c)[1 mark]
Explain what is lost if separation immediately divides by .
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) Both satisfy it. (b) Every stated delayed solution satisfies it. (c) Zero-valued solution portions are excluded.
Worked solution
(a) For zero y the derivative and square root are zero. For , the derivative and square root are both t/2 on nonnegative t. Both have initial value zero.
(b) Before c, both sides are zero; after c, both sides equal (t-c)/2. At c the pieces agree at zero. Both one-sided derivatives are zero, so y is differentiable there and satisfies the equation at the join.
(c) Division assumes y>0, discarding the zero solution and possible waiting intervals. This initial-value problem does not have a unique solution.
Equivalent mathematically justified methods accepted.
Exact answers unless a decimal accuracy is specified.
Part a: Verify the zero solution.
Part a: Verify the quadratic solution and initial value.
Part b: Verify both open pieces.
Part b: Check continuity at the join.
Part b: Check the derivative and equation at the join.
Part c: Explain the excluded zero-valued portions.
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