Integration and applications of integration — Question 1
QCAA 2025, Paper 1 · 1 mark
Q1 · 2025 · Technology-freeSimple familiar1 mark
QUESTION 1
Use the substitution u=x2 to express ∫2xex2dx in terms of u. (A)∫eudu (B)∫21eudu (C)∫ueudu (D)∫2ueudu WORKED SOLUTION
Answer A
1 markWorked solution
With u=x2, du=2xdx. Therefore ∫2xex2dx=∫eudu. Worked explanation by QCE Vault; correct option verified against the QCAA answer key.
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