Q241 · Practice questionComplex unfamiliar6 marks
QUESTION 241 (6 marks)
An atom has the bound energy levels shown. An electron initially in the ground state absorbs one photon and reaches the highest shown level. It then returns to the ground state in exactly two radiative steps. The first emitted photon has energy . Use , and .
a)[2 marks]
Calculate the wavelength of the absorbed photon.
b)[2 marks]
Identify the intermediate level and justify it using the first emitted photon.
c)[2 marks]
Calculate the wavelength of the second emitted photon.
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) . (b) . (c) .
Worked solution
(a) The absorbed energy is . Thus .
(b) The first emission lowers the electron energy by , from to . This is a shown level and can then decay to the ground state.
(c) The second energy drop is . Thus . The emitted energies sum to , consistent with the absorbed energy.
Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
Part a: Determine and convert the ground-to-highest energy gap.
Part a: Calculate the absorbed photon wavelength.
Part b: Subtract the first emitted photon energy from the starting level.
Part b: Identify the matching shown intermediate level.
Part c: Determine and convert the remaining energy gap.
Part c: Calculate the second emitted wavelength.
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