QCEVault

Quantum theory — Question 274

Original QCE Vault practice · 5 marks

Q274 · Practice questionComplex unfamiliar5 marks

QUESTION 274 (5 marks)

In a photoelectric experiment the collector potential relative to the emitter at zero photocurrent is Vc=−VsV_c=-V_s, where VsV_s is the positive stopping-potential magnitude. A fitted graph of VsV_s against frequency passes through (6.00×1014 Hz,0.500 V)(6.00\times10^{14}\,\mathrm{Hz},0.500\,\mathrm V) and (9.00×1014 Hz,1.74 V)(9.00\times10^{14}\,\mathrm{Hz},1.74\,\mathrm V). Use e=1.60×10−19 Ce=1.60\times10^{-19}\,\mathrm C.
Positive stopping-potential magnitude versus frequency, with an exact fitted line through the two stated coordinates.
a)
Use the fit to determine Planck extquotesingle s constant and the work function in eV.
[3 marks]
b)
Determine the collector potential required to stop the most energetic electrons at f=8.00×1014 Hzf=8.00\times10^{14}\,\mathrm{Hz}.
[2 marks]
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