QUESTION 26 (5 marks)
Aqueous potassium iodate (KIO3) reacts with aqueous potassium iodide (KI) in the presence of dilute HCl(aq) to form solid iodine (I2). The overall balanced equation is shown.
a) Identify the reducing agent. Explain your reasoning.
[2 marks]
b) Determine the reduction half-equation.
[3 marks]
QCAA guide · typeset solution
QCAA sample response and mark allocation
26a) | I–(aq) in KI is the reducing agent because it loses an electron to be oxidised to I2(s). | • identifies that the iodide ion (I–) in KI is the reducing agent [1 mark] • explains I– is oxidised by losing an electron [1 mark] |
26b) | Reduction half-equation: + − 2IO (aq) + 12H (aq) + 10 e I ( ) s + 6H O ( l ) 3 2 2 | • determines IO3– + H+ + e– are reactants [1 mark] • determines I2 + H2O are products [1 mark] • determines the balanced reduction half-equation [1 mark] |
QCAA sample response and marking criteria reproduced from the official guide.
Compare your working with the guide above.