Vectors in three dimensions — Question 116
Original QCE Vault practice · 1 mark
Q116 · Practice questionTechnology-freeComplex familiar1 mark
QUESTION 116
The area of the parallelogram generated by a=(1,2,0) and b=(0,1,2) is WORKED SOLUTION
Answer B
1 markWorked solution
a×b=(4,−2,1), so area=∣a×b∣=16+4+1=21. Selects the correct option.
[1 mark]Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
View the QCAA syllabusRelated questions
- Q3 · Original practice · 1 mark
Original Specialist Mathematics practice question 3: line and plane
Vectors in three dimensions - Q8 · Original practice · 5 marks
Original Specialist Mathematics practice question 8: line-plane geometry
Vectors in three dimensions - Q24 · Original practice · 6 marks
Let a=(4,−2,4) and b=(1,2,2). Vectors in three dimensions - Q26 · Original practice · 6 marks
The sphere x2+y2+z2=9 is intersected by the line r=(0,0,4)+t(1,0,−1). Vectors in three dimensions