Let w=rcis(θ). By De Moivre’s theorem, w7=r7cis(7θ). Since w=x+i,
θ=tan−1(1/x).
The condition Re(w7)=0 requires
7θ=(2n+1)2π,
so
x=cot(14(2n+1)π).
Because x>0, the admissible first-quadrant angles yield
x=cot14π,cot143π,cot145π.
correctly uses De Moivre’s theorem
[1 mark]
correctly determines an expression representing arg(w) in terms of x
[1 mark]
determines a relationship involving arg(w7) using the condition Re(w7)=0
[1 mark]
determines a general expression representing possible values of x
[1 mark]
determines one value of x
[1 mark]
evaluates the reasonableness of the solution by determining the remaining two values of x
[1 mark]
One QCAA sample method typeset for web; criterion wording is adapted from the official marking guide.