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Mechanics — Question 89

Original QCE Vault practice · 1 mark

Q89 · Practice questionSimple familiar1 mark

QUESTION 89

A vertical-motion model uses dv/dt=−9.8−0.4vdv/dt=-9.8-0.4v, where upward velocity is positive. The terminal speed is
(A)
9.8 m s−19.8\ \mathrm{m\,s^{-1}}
(B)
19.6 m s−119.6\ \mathrm{m\,s^{-1}}
(C)
24.5 m s−124.5\ \mathrm{m\,s^{-1}}
(D)
39.2 m s−139.2\ \mathrm{m\,s^{-1}}
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