Mechanics — Question 89
Original QCE Vault practice · 1 mark
Q89 · Practice questionSimple familiar1 mark
QUESTION 89
A vertical-motion model uses dv/dt=−9.8−0.4v, where upward velocity is positive. The terminal speed is (A)9.8 ms−1 (B)19.6 ms−1 (C)24.5 ms−1 (D)39.2 ms−1 WORKED SOLUTION
Answer C
1 markWorked solution
At terminal velocity, 0=−9.8−0.4v, so v=−24.5 ms−1. The terminal speed is its magnitude, 24.5 ms−1. Selects the correct option.
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