Q280 · Practice questionTechnology-freeSimple familiar6 marks
QUESTION 280 (6 marks)
A trolley has acceleration m s for s and initial velocity m s. The acceleration graph is supplied.
a)[2 marks]
Determine v(t) and the times at which the trolley reverses direction.
b)[2 marks]
Sketch the velocity-time graph. Label the roots, endpoint values and maximum.
c)[2 marks]
Determine the total distance travelled during the six seconds.
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) ; reversals at 1 s and 5 s. (b) Downward parabola; zeros at 1 and 5 s, maximum at , and endpoint velocities m/s. (c) m.
Worked solution
(a) Integrate acceleration: , and . Factor ; its sign changes at both roots.
(b) The vertex is at , where and . The intervals of positive and negative velocity agree with the reversal analysis.
(c) An antiderivative of v is . It gives , and . Integrating speed in three pieces gives m.
Equivalent justified methods accepted; respect any requested proof method.
Exact values unless specified. Sketches assessed by mathematical features, not artistic quality.
Part a: Integrate and apply the initial condition.
Part a: Find the two roots and check reversal.
Part b: Draw and label roots and endpoints.
Part b: Draw and label the correct maximum.
Part c: Split the speed integral at both reversals.
Part c: Evaluate the sum as m.
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