Q271 · Practice questionTechnology-freeComplex familiar6 marks
QUESTION 271 (6 marks)
The polynomial has . Its remainder on division by is , and .
a)[3 marks]
Use the remainder theorem to determine a and b.
b)[3 marks]
Factorise P completely over . Explain why real-coefficient conjugate-root reasoning cannot be assumed.
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) , . (b) .
Worked solution
(a) , so . Also , so . Thus , giving and .
(b) Dividing by gives . The quadratic formula gives the remaining roots . Therefore
The coefficients a and b are not both real, so the conjugate-root theorem for real coefficients does not apply.
Equivalent justified methods accepted; respect any requested proof method.
Exact values unless specified. Sketches assessed by mathematical features, not artistic quality.
Part a: Form the remainder equation .
Part a: Use and solve for a.
Part a: Find b and check both conditions.
Part b: Divide by the known factor to obtain .
Part b: Solve the quadratic and factor completely.
Part b: Explain the limitation of conjugate-root reasoning.
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