Q261 · Practice questionTechnology-freeComplex familiar5 marks
QUESTION 261 (5 marks)
A graphics tool maps a complex number to . Assume .
a)[2 marks]
Show that the mapping is defined for every permitted z.
b)[3 marks]
Prove that for every permitted z.
WORKED SOLUTION
5 marksPractice marking scheme
ANSWER
(a) whenever . (b) The unit circle maps into the unit circle.
Worked solution
(a) The only possible zero denominator occurs at , whose modulus is , so it is excluded by the given condition.
(b) Using ,
These are equal, and the denominator is nonzero by (a). The quotient modulus identity gives .
Equivalent justified methods accepted; respect any requested proof method.
Exact values unless specified. Sketches assessed by mathematical features, not artistic quality.
Part a: Find the only candidate zero denominator.
Part a: Use its modulus to exclude it.
Part b: Expand the numerator squared modulus using .
Part b: Expand the denominator and establish equality.
Part b: Apply the quotient identity with a valid denominator.
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