Q215 · Practice questionTechnology-activeComplex unfamiliar8 marks
QUESTION 215 (8 marks)
A survival model, with t in hours, is
a)[3 marks]
Determine the median lifetime to four decimal places.
b)[2 marks]
Given survival to 3 hours, find mean additional lifetime and explain why T is not a single exponential variable.
c)[3 marks]
For 100 independent items that have each survived to 3 hours, let be their mean additional lifetime. The exponential standard deviation equals its mean. Use the central limit theorem to approximate to four decimal places.
WORKED SOLUTION
8 marksPractice marking scheme
ANSWER
(a) h. (b) h additional; its rate changes. (c) approximately.
Worked solution
(a) Survival at 3 is exp(-0.6)>1/2, so use the second branch. Solving gives the stated exact expression and decimal.
(b) for u nonnegative, so the remaining lifetime is exponential with mean 1/0.4=2.5. The full distribution changes rate from 0.2 to 0.4, so cannot have one constant exponential rate.
(c) Each additional lifetime has mean and standard deviation 2.5 hours from (b). Thus the sample mean has mean 2.5 and standard error . The requested normal approximation is . Normality is approximate: individual additional lifetimes are exponential.
Equivalent mathematically justified methods accepted.
Exact answers unless a decimal accuracy is specified.
Part a: Identify the second branch.
Part a: Solve the median equation.
Part a: Report 3.2329 h.
Part b: Obtain conditional survival and its mean.
Part b: Explain why the complete model has no single rate.
Part c: Find the sample-mean mean and standard error.
Part c: Standardise the correct event.
Part c: Calculate the approximate upper tail.
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