Electromagnetism — Question 124
Original QCE Vault practice · 1 mark
Q124 · Practice questionComplex familiar1 mark
QUESTION 124
A +3.0 microC charge moves through a potential difference of −20V. Its change in electric potential energy is (A)−1.5×10−7J (C)+6.0×10−5J (D)−6.0×10−5J WORKED SOLUTION
Answer D
1 markANSWERD. −6.0×10−5J Worked solution
ΔU=qΔV=(3.0×10−6)(−20)=−6.0×10−5J. Selects the correct option.
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