Q25 · 2025 · Paper 1Complex unfamiliar11 marks
QUESTION 25 (11 marks)
An experiment was conducted by launching a ball with an initial velocity of at varying angles from the horizontal from a height of 1.0 m above the ground. The horizontal displacement was recorded to produce the graph shown.
a)[2 marks]
Identify the trend between horizontal displacement and angle of release.
b)[5 marks]
Determine the experimental time taken for the ball to land when released at an angle of . Show your working.
c)[4 marks]
Determine the maximum height from the ground that the ball could reach using this set-up. Show your working.
WORKED SOLUTION
11 marksQCAA guide · typeset solution
ANSWER
See worked solution below.
Worked solution
a) As the angle of release increases, the horizontal displacement increases, up until . After this, as the angle increases, the range decreases.
b)
(from graph)
Time taken =
c) Maximum height is when initial velocity = vertical velocity i.e. when launch angle = .
Since initial height = 1.0 m (from question):
Maximum height =
identifies the trend
uses data from the graph
calculates horizontal velocity
identifies horizontal range from graph
recognises that the scenario relates to horizontal displacement
provides appropriate mathematical reasoning
determines time taken
indicates launch angle = 90°
recognises that the scenario relates to an object undergoing projectile motion
calculates vertical displacement
determines the maximum height
One QCAA sample method typeset for web; criterion wording is adapted from the official marking guide.
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Compare your working with the guide above.