Q167 · Practice questionComplex familiar5 marks
QUESTION 167 (5 marks)
A proton starts from rest at electric potential and moves to a point at . Only the electric force does work. Use and .
a)[2 marks]
Determine the change in electric potential energy of the proton.
b)[3 marks]
Determine the work done by the electric field and the final speed of the proton.
WORKED SOLUTION
5 marksPractice marking scheme
ANSWER
(a) . (b) ; .
Worked solution
(a) . Thus .
(b) . This becomes kinetic energy, so . Hence , much smaller than .
Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
Part a: Use the final-minus-initial potential difference.
Part a: Calculate the signed potential-energy change.
Part b: Use field work as the negative potential-energy change.
Part b: Equate field work to kinetic-energy gain.
Part b: Calculate the final speed.
Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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