Q165 · Practice questionComplex unfamiliar6 marks
QUESTION 165 (6 marks)
Two fixed point charges are positioned relative to O: is to the left and is above. Use .
a)[4 marks]
Determine the magnitude and direction of the resultant electric field at O.
b)[2 marks]
Determine the force on an electron placed at O. Use charge magnitude .
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) , above the rightward horizontal. (b) , below the leftward horizontal.
Worked solution
(a) The positive charge produces a rightward field . The negative charge produces an upward field . Hence and .
(b) . The force on a negative charge is opposite to the field.
Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
Part a: Calculate the horizontal field with its direction.
Part a: Calculate the vertical field with its direction.
Part a: Recombine components for magnitude.
Part a: Determine the direction of the resultant.
Part b: Calculate the force magnitude.
Part b: Reverse the field direction for the electron.
Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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