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Electromagnetism — Question 231

Original QCE Vault practice · 5 marks

Q231 · Practice questionComplex unfamiliar5 marks

QUESTION 231 (5 marks)

Fixed charges +2.00 μC+2.00\,\mu\mathrm C and −2.00 μC-2.00\,\mu\mathrm C lie 0.300 m0.300\,\mathrm m left and right of O, respectively. P is 0.400 m0.400\,\mathrm m directly above O. Use k=9.00×109 N m2 C−2k=9.00\times10^9\,\mathrm{N\,m^2\,C^{-2}}.
Positive and negative 2.00 microcoulomb charges are equally spaced 0.300 m left and right of O. P is on a dotted vertical 0.400 m above O. Charge values are above their symbols. No third charge is drawn at P. Not to scale.
a)
Determine the resultant electric field at O due to the two fixed charges.
[3 marks]
b)
Could any choice of a third point charge placed at P make the resultant electric field at O zero? Explain.
[2 marks]
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