Electromagnetism — Question 206
Original QCE Vault practice · 1 mark
Q206 · Practice questionComplex familiar1 mark
QUESTION 206
An electron moves from electric potential +80.0V to +180V. Use q=−1.60×10−19C. What is its change in electrical potential energy? (A)+1.60×10−17J (B)−4.16×10−17J (C)+4.16×10−17J (D)−1.60×10−17J WORKED SOLUTION
Answer D
1 markANSWERD. −1.60×10−17J Worked solution
ΔU=qΔV=(−1.60×10−19)(180−80)=−1.60×10−17J. A rise in potential decreases the potential energy of a negative charge. Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
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