QCEVault

Electromagnetism — Question 259

Original QCE Vault practice · 3 marks

Q259 · Practice questionComplex familiar3 marks

QUESTION 259 (3 marks)

A negatively charged oil drop of mass 3.20×10−15 kg3.20\times10^{-15}\,\mathrm{kg} is held stationary in a uniform downward electric field of 4.90×104 N C−14.90\times10^4\,\mathrm{N\,C^{-1}}. Use g=9.80 m s−2g=9.80\,\mathrm{m\,s^{-2}} and e=1.60×10−19 Ce=1.60\times10^{-19}\,\mathrm C.
a)
Determine the charge on the drop, including its sign.
[2 marks]
b)
How many excess electrons does the drop carry?
[1 mark]
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