Q130 · Practice questionComplex familiar4 marks
QUESTION 130 (4 marks)
At 25 °C, 20.0 mL of 0.0600 mol L⁻¹ HCl is mixed with 15.0 mL of 0.0500 mol L⁻¹ Ba(OH)₂. Assume complete dissociation and additive volumes.
(a) Determine which ion is in excess after neutralisation, and calculate its remaining amount. [2 marks]
(b) Calculate the pH of the mixture. [2 marks]
WORKED SOLUTION
4 marksPractice marking scheme
Answer
OH⁻ is in excess by mol. and pH = 11.93.
Working
mol. Each Ba(OH)₂ gives two OH⁻ ions, so mol. Excess OH⁻ is 0.000300 mol in 0.0350 L. Hence and .
Marking criteria
- Calculates the H⁺ and OH⁻ amounts, using two OH⁻ per Ba(OH)₂. [1 mark]
- Identifies excess OH⁻ and calculates 3.00 × 10⁻⁴ mol remaining. [1 mark]
- Calculates [OH⁻] using the total volume 35.0 mL. [1 mark]
- Calculates pH = 11.93. [1 mark]
Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
View the QCAA syllabusHow many marks did you earn?
Compare your working with the guide above.