Q87 · Practice questionComplex unfamiliar6 marks
QUESTION 87 (6 marks)
50.0 mL of 0.100 mol L⁻¹ AgNO₃ is mixed with 50.0 mL of 0.100 mol L⁻¹ NaCl at . AgCl precipitates. For AgCl, . After equilibrium, the liquid is completely separated from the solid. Use .
a) Calculate the equilibrium silver-ion concentration in the liquid. [2 marks]
b) Calculate the theoretical charge needed to reduce all dissolved Ag⁺ in the 100.0 mL liquid to Ag, assuming no competing reaction. [3 marks]
c) Explain why leaving the AgCl solid in contact with the liquid would invalidate this calculation as a prediction of total available silver. [1 marks]
WORKED SOLUTION
6 marksPractice marking scheme
; charge = 0.129 C; solid can dissolve as Ag⁺ is consumed.
Equal starting ion amounts leave , hence . Moles dissolved Ag⁺=; one electron each gives C. Removal of Ag⁺ lowers Qsp and allows more solid to dissolve.
- Recognises equal remaining ion concentrations. [1 marks]
- Calculates [Ag⁺] from √Ksp. [1 marks]
- Calculates dissolved silver moles. [1 marks]
- Uses one electron per Ag⁺. [1 marks]
- Calculates charge 0.129 C. [1 marks]
- Explains further solid dissolution as Ag⁺ is removed. [1 marks]
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