QUESTION 5 (17 marks)
Compound A reacts with water to produce compound B and hydroxide ions.
+ –
CH CH NH (aq) + H O(l)
ƒ C H NH (aq) + OH (aq)
3 2 2 2 2 5 3
A
B
a) Apply IUPAC rules to name compound A.
[1 mark]
b) Identify the Brønsted-Lowry acids in the equation.
[2 marks]
c) A small amount of hydrochloric acid is added to the equilibrium mixture. Predict the effect of this on the concentration of compound A in the mixture. Explain your reasoning.
[3 marks]
d) Calculate the pH of a 2.0 M solution of compound A. State any assumptions.
4 -
Show your working. (
) 5.6 10 K ́
[6 marks]
b
e) Describe, using a balanced chemical equation, how Compound A could be made from bromomethane. Include relevant conditions and reagents in your response.
[5 marks]
QCAA guide · typeset solution
QCAA sample response and mark allocation
5 | a) | ethanamine | • provides ethanamine [1 mark] | |
b) | H2O(l)C2H5NH3 +(aq) | • provides H2O(l) [1 mark] • provides C2H5NH3 +(aq) [1 mark] | ||
c) | The hydrochloric acid (H+) reacts with the OH− ions and decreases their concentration. According to Le Châtelier’s principle, this will make the equilibrium position shift to the right to counteract decrease in OH− (products). Therefore, the concentration of A will decrease. | • indicates that [OH−] will decrease [1 mark] • indicates that the equilibrium will shift right [1 mark] • indicates that A will decrease [1 mark] |
d) | [CH3CH2NH2] = 2.0 −x ≈2.0 as 2.0 ≫ KKb +] = [OH−] Let x = [C2H5NH3 +][OH−] [C2H5NH3 KKb = [CH3CH2NH2] [x][x] [2.0] = x2 5.6 × 10−4 = 2.0 x2 = 1.12 × 10−3 x = 0.033466 = [OH−] pOH = –log [OH−] = 1.475 ≈ 1.5 pH = 14 −1.5 = 12.5 pH = 12.5 (to 1 decimal place) | • indicates assumption to support [CH3CH2NH2] ≈2.0 [1 mark] +] = • indicates [C2H5NH3 [OH−] [1 mark] • shows substitution correctly performed [1 mark] • determines [OH−] = 3.35 × 10−2 [1 mark] • determines pOH [1 mark] • determines pH [1 mark] | Accept ICE table. Allow FT error from [OH−]. Do not penalise for incorrect decimal places/significant figures. |
e) | Heat CH3Br with KCN under reflux to produce CH3CN and KBr heat with Ni catalyst CH3CN(aq) + 2H2(g) ሱ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ሮ CH3CH2NH2(aq) | • indicates CH3Br reacts with KCN to produce KH3CN and KBr [1 mark] • identifies reaction is heated under reflux in ethanol [1 mark] • indicates CH3CN reacts with H2(g) to produce CH3CH2NH2 [1 mark] • indicates heat and Ni/Pt/Pd catalyst required [1 mark] • represents one of the reactions as a balanced chemical equation [1 mark] | Also accept as balanced equation: CH3Br(aq) heat under reflux with KCN (ethanol) ሱ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ሮCH3CN(aq) + KBr(aq) |
QCAA sample response and marking criteria reproduced from the official guide.
Compare your working with the guide above.