Differential equations — Question 128
Original QCE Vault practice · 6 marks
Q128 · Practice questionTechnology-freeComplex unfamiliar6 marks
QUESTION 128 (6 marks)
A curve satisfies dxdy=y−12x+1 and passes through (0,3). a)Find y explicitly in terms of x, selecting the branch satisfying the initial condition. [4 marks] b)Find the tangent equation at x=1. [2 marks] WORKED SOLUTION
Practice marking scheme
6 marksANSWERAt x=1,y=1+8=1+22. Slope=223=432. Tangent: y−(1+22)=(432)(x−1). Worked solution
Part (a): Separate: (y−1)dy=(2x+1)dx. Integrate: 0.5(y−1)2=x2+x+C. At (0,3),C=2. Thus (y−1)2=2x2+2x+4. Since y(0)=3, choose positive branch y=1+2x2+2x+4. Part (b): At x=1,y=1+8=1+22. Slope=223=432. Tangent: y−(1+22)=(432)(x−1). Part (a): completes the requested reasoning and obtains a correct result.
[4 marks]Part (b): completes the requested reasoning and obtains a correct result.
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