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Vectors and matrices — Question 9

QCAA 2022, Paper 2 · 1 mark

Q9 · 2022 · Technology-activeSimple familiar1 mark

QUESTION 9

Consider the matrix equation X[001011111]=[122212221]X\begin{bmatrix}0&0&1\\0&1&1\\1&1&1\end{bmatrix}=\begin{bmatrix}1&2&2\\2&1&2\\2&2&1\end{bmatrix}. Matrix XX is
(A)
[0111−12−102]\begin{bmatrix}0&1&1\\1&-1&2\\-1&0&2\end{bmatrix}
(B)
[01−11−10122]\begin{bmatrix}0&1&-1\\1&-1&0\\1&2&2\end{bmatrix}
(C)
[221433555]\begin{bmatrix}2&2&1\\4&3&3\\5&5&5\end{bmatrix}
(D)
[245235135]\begin{bmatrix}2&4&5\\2&3&5\\1&3&5\end{bmatrix}
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