Vector calculus — Question 38
Original QCE Vault practice · 5 marks
Q38 · Practice questionComplex familiar5 marks
QUESTION 38 (5 marks)
A particle has position r(t)=5(cos2t,sin2t). a)Show that its speed is constant and determine that speed.
[2 marks] b)Show that a=−4r. [2 marks] c)Determine the period of the motion.
[1 mark] WORKED SOLUTION
Practice marking scheme
5 marksANSWER(a) 10; (b) a=−4r; (c) π. Worked solution
(a) v=10(−sin2t,cos2t). Hence ∣v∣=10sin22t+cos22t=10, independent of t. (b) Differentiating again gives a=−20(cos2t,sin2t)=−4r. (c) The angular speed is 2, so T=2π/2=π. Obtains velocity and constant speed.
[2 marks]Establishes the acceleration relation.
[2 marks]Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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