Complex numbers — Question 12
Original QCE Vault practice · 6 marks
Q12 · Practice questionComplex familiar6 marks
QUESTION 12 (6 marks)
Let z=−3+33i. a)Express z in the form rcisθ, where 0≤θ<2π. [2 marks] b)Determine z4 in Cartesian form. [2 marks] c)Determine all solutions of w3=z in polar form. [2 marks] WORKED SOLUTION
Practice marking scheme
6 marksANSWER(a) 6cis(2π/3); (b) −648+6483i; (c) 36cis(2π/9+2kπ/3), k=0,1,2. Worked solution
(a) ∣z∣=9+27=6 and z is in quadrant II with reference angle π/3. Thus z=6cis(2π/3). (b) By De Moivre’s theorem, z4=64cis(8π/3)=1296cis(2π/3)=−648+6483i. (c) The cube roots have modulus 36 and arguments 32π/3+2kπ=92π+32kπ,k=0,1,2. Therefore the roots are 36cis(2π/9), 36cis(8π/9) and 36cis(14π/9). Correct modulus and argument.
[2 marks]Correct use of De Moivre’s theorem and Cartesian result.
[2 marks]All three cube roots with correct moduli and arguments.
[2 marks]Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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