QCEVault

Integration — Question 65

Original QCE Vault practice · 1 mark

Q65 · Practice questionSimple familiar1 mark

QUESTION 65

For x=0,0.5,1.0,1.5,2.0x=0,0.5,1.0,1.5,2.0, a function has values 1.0,1.5,2.2,3.1,4.21.0,1.5,2.2,3.1,4.2. Simpson’s rule with four intervals gives ∫02f(x) dx≈\displaystyle\int_0^2 f(x)\,dx\approx
(A)
4.20004.2000
(B)
4.50004.5000
(C)
4.66674.6667
(D)
4.90004.9000
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