Integration — Question 51
Original QCE Vault practice · 1 mark
Q51 · Practice questionSimple familiar1 mark
QUESTION 51
The exact value of ∫0π/2sin2xdx is WORKED SOLUTION
Answer B
1 markWorked solution
Use sin2x=(1−cos2x)/2: ∫0π/2sin2xdx=[2x−4sin2x]0π/2=4π. Selects the correct option.
[1 mark]Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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