Vectors in two and three dimensions — Question 288
Original QCE Vault practice · 1 mark
Q288 · Practice questionTechnology-freeSimple familiar1 mark
QUESTION 288
A position vector is a=3i+4j+5k. Its altitude angle above the xy-plane is (D)arctan(5/3) WORKED SOLUTION
Answer A
1 markWorked solution
The horizontal magnitude is 32+42=5. Therefore tanϕ=5/5=1 and ϕ=π/4. Equivalent justified methods accepted; respect any requested proof method.
Exact values unless specified. Sketches assessed by mathematical features, not artistic quality.
Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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