Q166 · Practice questionTechnology-freeComplex familiar6 marks
QUESTION 166 (6 marks)
Two planes have Cartesian equations
Their line of intersection is . The diagram is schematic.
a)[2 marks]
Use a cross product to determine a direction vector for .
b)[2 marks]
Determine a vector equation for .
c)[2 marks]
Determine the acute angle between the planes, exactly and to two decimal places in degrees.
WORKED SOLUTION
6 marksPractice marking scheme
ANSWER
(a) is a direction vector. (b) , . (c) Acute angle degrees.
Worked solution
(a) Normal vectors are and . Their cross product is , so is a direction vector for the intersection.
(b) Subtract the equations to obtain , hence . Either plane then gives . Set , , so
Both plane equations hold for every real .
(c) The acute angle between the planes equals the acute angle between their normals:
Thus degrees. The direction vector of the intersection is perpendicular to both normals.
Equivalent mathematically justified methods accepted.
Exact answers unless a decimal accuracy is specified.
Part a: Identify both normal vectors.
Part a: Compute a nonzero cross product parallel to (1,0,-1).
Part b: Find a point on both planes.
Part b: Give a correct vector equation and real parameter domain.
Part c: Use the normal-vector scalar product to obtain cosine 1/3.
Part c: Give arccos(1/3) and 70.53 degrees.
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