Q156 · Practice questionTechnology-activeComplex unfamiliar7 marks
QUESTION 156 (7 marks)
An insect population has juvenile and adult stages. The model is
The entries are expected population counts; fractional values are permitted. The stage diagram shows the transitions in one time step.
a)[2 marks]
Determine the stage counts after two time steps and the proportion of adults at that time.
b)[3 marks]
Suppose the ratio remains constant at a positive value . Derive and solve an equation for .
c)[2 marks]
Determine the population growth factor at this stable composition. Give it exactly and to three decimal places.
WORKED SOLUTION
7 marksPractice marking scheme
ANSWER
(a) ; adult proportion . (b) . (c) Growth factor .
Worked solution
(a) The first two updates give and . Hence the adult proportion is .
(b) In a stable composition let . Then
Equating this to gives , so . The negative root is inadmissible; therefore .
(c) . At this composition the adult count has the same factor, so total population also multiplies by approximately 1.281 each step. This predicts growth of approximately 28.1% per step. The finite-time adult proportion in part (a) is not the stable ratio .
Equivalent mathematically justified methods accepted.
Exact answers unless a decimal accuracy is specified.
Part a: Correctly iterate to (300,175).
Part a: Obtain adult proportion 7/19.
Part b: Express the next ratio as (1+r)/(4r).
Part b: Obtain 4r squared minus r minus 1=0.
Part b: Select the positive root (1+sqrt(17))/8.
Part c: Relate the growth factor to 2r.
Part c: Give the exact factor and 1.281.
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