Q181 · Practice questionComplex familiar7 marks
QUESTION 181 (7 marks)
An electron and a positron initially at rest annihilate into two photons travelling in opposite directions with equal energies. Use , , and .
a)[3 marks]
Determine the energy of each photon in joules and MeV.
b)[2 marks]
Determine the wavelength of each photon.
c)[2 marks]
Explain why opposite photon directions are consistent with momentum conservation.
WORKED SOLUTION
7 marksPractice marking scheme
ANSWER
(a) ; . (b) . (c) Equal and opposite photon momenta sum to zero, matching the initially stationary pair.
Worked solution
(a) Total initial rest energy is . Each photon receives half, so . Dividing by gives .
(b) .
(c) The initial total momentum is zero. Each photon has momentum magnitude ; equal energies and opposite directions make the final vector sum zero. A single nonzero-energy photon could not give zero final momentum in this isolated situation.
Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
Part a: Determine total rest energy and divide between two photons.
Part a: Calculate the photon energy in joules.
Part a: Convert that energy to MeV.
Part b: Use the photon energy–wavelength relation.
Part b: Calculate the wavelength.
Part c: Identify zero initial total momentum.
Part c: Explain cancellation of the final photon momenta.
Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.
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