Q234 · Practice questionComplex familiar5 marks
QUESTION 234 (5 marks)
A rectangular conducting loop has horizontal width , vertical height and total resistance . It moves right at into a uniform field directed into the page. Outside the field, B is zero. Ignore self-inductance. Consider an instant when only part of the loop is inside the field.
a)[2 marks]
Calculate the magnitude of the induced EMF during entry.
b)[2 marks]
Determine the current magnitude and direction, viewed as drawn.
c)[1 mark]
State the induced EMF once the loop is completely inside the uniform field and continues moving at the same velocity.
WORKED SOLUTION
5 marksPractice marking scheme
ANSWER
(a) . (b) , counterclockwise. (c) Zero.
Worked solution
(a) The area inside the field increases at rate . For one loop, .
(b) . The into-page flux is increasing, so the induced field points out of the page; the current is counterclockwise.
(c) The loop's area, orientation and enclosed uniform B are then constant, so its flux is constant and Faraday's law gives zero EMF.
Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
Part a: Determine the rate of change of enclosed field area.
Part a: Apply Faraday\textquotesingle s law to calculate the EMF.
Part b: Calculate current from EMF and resistance.
Part b: Use Lenz\textquotesingle s law to give the counterclockwise direction.
Part c: Relate constant enclosed flux to zero induced EMF.
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