QCEVault

Gravity and motion — Question 226

Original QCE Vault practice · 5 marks

Q226 · Practice questionComplex unfamiliar5 marks

QUESTION 226 (5 marks)

A ball is launched from height 1.00 m1.00\,\mathrm m with horizontal velocity 12.0 m s−112.0\,\mathrm{m\,s^{-1}}. A thin vertical screen is 18.0 m18.0\,\mathrm m horizontally from the launch point. Its opening extends from 4.80 m4.80\,\mathrm m to 5.40 m5.40\,\mathrm m above the same ground level. Ignore drag and ball size. Use g=9.8 m s−2g=9.8\,\mathrm{m\,s^{-2}}.
A ball launches up and right from height 1.00 m. A vertical screen 18.0 m away has an opening between horizontal dotted levels at 4.80 m and 5.40 m, measured above the ground. Separate dotted vertical guides mark the horizontal distance. Not to scale.
a)
Determine the range of initial upward velocity components that allows the ball to pass through the opening without touching either edge.
[3 marks]
b)
The ball is instead launched with ux=14.0 m s−1u_x=14.0\,\mathrm{m\,s^{-1}} and uy=10.0 m s−1u_y=10.0\,\mathrm{m\,s^{-1}}. Determine whether it passes through the opening.
[2 marks]
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