Q225 · Practice questionComplex familiar5 marks
QUESTION 225 (5 marks)
A small ball is launched horizontally at from a platform above level ground. A small ground-level catcher moves in the same direction at constant speed . At launch it is distance ahead of the point directly below the ball. Ignore drag and object sizes. Use .
a)[2 marks]
Calculate the time at which the ball reaches ground level.
b)[3 marks]
Determine d so that the ball enters the catcher at ground level.
WORKED SOLUTION
5 marksPractice marking scheme
ANSWER
(a) . (b) .
Worked solution
(a) The initial vertical velocity is zero. With downward positive, , so .
(b) At the ball is from its launch vertical. The catcher is at . Setting their positions equal gives .
Equivalent physically justified methods and consistent equivalent units accepted.
Displayed decimals are model answers; accept appropriate significant figures and consistent rounding from stated constants.
Part a: Use the vertical displacement equation independently of horizontal motion.
Part a: Calculate the positive fall time.
Part b: Determine the ball\textquotesingle s horizontal displacement.
Part b: Express the moving catcher\textquotesingle s position using d.
Part b: Equate positions and calculate the initial separation.
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