a) 831.1528 m; b) 220232.7922 m2; c) approximately 341124 m2.
Worked solution
a) Use the cosine rule: c=9002+5402−2(900)(540)cos65∘=831.1528 m.
b) A=21(900)(540)sin65∘=220232.7922 m2.
c) **Method 1.** Use the sine rule for the second triangle: 500sinD=831.1528sin110∘, so D=34.4228∘. The remaining angle is 180∘−(110∘+34.4228∘)=35.5772∘. Hence the second-triangle area is 21(831.1528)(500)sin35.5772∘=120891.0424 m2, and the total area is 220232.7922+120891.0424=341123.8346 m2.
**Method 2.** Alternatively, use the cosine rule: 831.15282=a2+5002−2(a)(500)cos110∘, giving a=514.599 m. Then the second-triangle area is 21(500)(514.599)sin110∘=120891.2207 m2, and the total area is 341124.0129 m2.
correctly determines the length of the internal fence
[1 mark]
correctly determines the triangle area
[1 mark]
uses an appropriate trigonometric rule with appropriate substitutions evident
[1 mark]
determines the required angle or unknown side length needed to determine the area of the second triangle