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Mathematical Methods — Question 4

QCAA 2023, Paper 1 · 1 mark

Q4 · 2023 · Technology-freeSimple familiar1 mark

QUESTION 4

Given

f'(x)=\frac{20}{x^3}

, an antiderivative is

(A)

\frac{10}{x^2}+c

(B)

-\frac{20}{x^2}+c

(C)

-\frac{10}{x^2}+c

(D)

10x^{-3}+c

ABCD

Question linkOriginal paper

WORKED SOLUTION

Answer C

1 mark

ANSWER

C —

-\frac{10}{x^2}+c

Worked solution

\int20x^{-3}dx=-10x^{-2}+c=-10/x^2+c

; C.

Selects option C.

[1 mark]

Worked explanation by QCE Vault; correct option verified against the QCAA answer key.

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