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Differentiation of trigonometric functions and differentiation rules — Question 158

Original QCE Vault practice · 1 mark

Q158 · Practice questionTechnology-freeSimple familiar1 mark

QUESTION 158

The graph of y=sin⁡(2x)y=\sin(2x) is shown with the point x=π8x=\dfrac{\pi}{8} marked. The gradient of the tangent at this point is
Graph of y equals sine of 2x with the point at x equals pi over 8 marked.
(A)
22\dfrac{\sqrt2}{2}
(B)
11
(C)
2\sqrt2
(D)
22
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