Further integration — Question 66

Original QCE Vault practice · 1 mark

Q66 · Practice questionTechnology-freeSimple familiar1 mark

QUESTION 66

An antiderivative of

\dfrac{6x}{3x^2+4}

(A)

\dfrac1{3x^2+4}+C

(B)

\ln(3x^2+4)+C

(C)

6\ln(3x^2+4)+C

(D)

\dfrac12\ln(3x^2+4)+C

ABCD

WORKED SOLUTION

1 mark

ANSWER

Worked solution

Let

u=3x^2+4

, so

du=6x\,dx

. Hence the integral is

\ln(3x^2+4)+C

Selects the correct option.

[1 mark]

Practice question aligned to the current QCAA syllabus; review the worked solution and marking criteria.