Q328 · Practice questionTechnology-freeComplex unfamiliar7 marks
QUESTION 328 (7 marks)
A hinged triangular shade has sides of lengths m and m meeting at a random angle radians. Its angle density is for , and zero otherwise.
a)[2 marks]
Verify that is a valid density.
b)[3 marks]
Determine the exact probability that the shade area is at least .
c)[2 marks]
Six independent shades use this angle model. Determine the probability that at least four meet the area requirement.
WORKED SOLUTION
7 marksPractice marking scheme
ANSWER
a) Nonnegative with integral 1. b) . c) .
Worked solution
a) on , and .
b) Area is . The requirement is , or . Integrate the density between these bounds to obtain .
c) The qualifying count is . The upper tail is .
Exact answers unless rounding is specified; equivalent forms accepted.
a) Checks nonnegativity.
a) Checks normalisation.
b) Forms the area inequality.
b) Determines the angle interval.
b) Integrates to obtain 1/2.
c) Uses a binomial model.
c) Gives the exact upper tail.
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